用Python怎么实现逆波兰表达式
用Python怎么实现逆波兰表达式？相信很多没有经验的人对此束手无策，为此本文总结了问题出现的原因和解决方法，通过这篇文章希望你能解决这个问题。
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逆波兰表达式是编译原理中的一种基本表达式，利用Python语言也可以实现逆波兰表达式的输出，这里举例实践说明：
什么是逆波兰表达式？
逆波兰表达式又叫做后缀表达式。在通常的表达式中，二元运算符总是置于与之相关的两个运算对象之间，所以，这种表示法也称为中缀表示。波兰逻辑学家J.Lukasiewicz于1929年提出了另一种表示表达式的方法。按此方法，每一运算符都置于其运算对象之后，故称为后缀表示。
举例实现：
# -*- coding: utf-8 -*-
symbol_priority = {}
symbol_priority[0] = ['#']
symbol_priority[1] = ['(']
symbol_priority[2] = ['+', '-']
symbol_priority[3] = ['*', '/']
symbol_priority[4] = [')']
def comparePriority(symbol, RPN_stack, symbol_stack):
'''Compare priority between two symbols'''
global symbol_priority
if len(symbol_stack) > 0:
symbol_pop = symbol_stack.pop()
else:
return
for list in symbol_priority.values():
if (symbol in list) and (symbol_pop in list):
'''same priority'''
symbol_stack.append(symbol_pop)
symbol_stack.append(symbol)
return
elif symbol in list:
'''symbol is smaller'''
RPN_stack.append(symbol_pop)
#recusion call
comparePriority(symbol, RPN_stack, symbol_stack)
return
elif symbol_pop in list:
'''symbol is bigger'''
symbol_stack.append(symbol_pop)
symbol_stack.append(symbol)
return
else:
continue
symbol_stack.append(symbol_pop)
return
def scanEveryone(input_string, RPN_stack, symbol_stack):
for ch in input_string:
if ch.isdigit():
RPN_stack.append(ch)
else:
if len(symbol_stack) > 0:
if ch == '(':
symbol_stack.append(ch)
elif ch == ')':
while True:
symbol_pop = symbol_stack.pop()
if symbol_pop == '(':
break
else:
RPN_stack.append(symbol_pop)
else:
comparePriority(ch, RPN_stack, symbol_stack)
else:
symbol_stack.append(ch)
def scanInput(RPN_stack, symbol_stack):
input_string = raw_input()
input_string += '#'
scanEveryone(input_string, RPN_stack, symbol_stack)
def calRPN(RPN_stack):
value_stack = []
RPN_stack.append('#')
for value in RPN_stack:
if value == '#':
return value_stack.pop()
break
if value.isdigit():
value_stack.append(value)
else:
right_value = value_stack.pop()
left_value = value_stack.pop()
cal_string = left_value + value + right_value
value_stack.append(str(eval(cal_string)))
def main():
RPN_stack = []
symbol_stack = []
scanInput(RPN_stack, symbol_stack)
print calRPN(RPN_stack)
if __name__ == '__main__':
main()calRPN.py
# -*- coding: utf-8 -*-
symbol_priority = {}
symbol_priority[0] = ['#']
symbol_priority[1] = ['(']
symbol_priority[2] = ['+', '-']
symbol_priority[3] = ['*', '/']
symbol_priority[4] = [')']
def comparePriority(symbol, RPN_stack, symbol_stack):
'''Compare priority between two symbols'''
global symbol_priority
if len(symbol_stack) > 0:
symbol_pop = symbol_stack.pop()
else:
return
for list in symbol_priority.values():
if (symbol in list) and (symbol_pop in list):
'''same priority'''
symbol_stack.append(symbol_pop)
symbol_stack.append(symbol)
return
elif symbol in list:
'''symbol is smaller'''
RPN_stack.append(symbol_pop)
#recusion call
comparePriority(symbol, RPN_stack, symbol_stack)
return
elif symbol_pop in list:
'''symbol is bigger'''
symbol_stack.append(symbol_pop)
symbol_stack.append(symbol)
return
else:
continue
symbol_stack.append(symbol_pop)
return
def scanEveryone(input_string, RPN_stack, symbol_stack):
for ch in input_string:
if ch.isdigit():
RPN_stack.append(ch)
else:
if len(symbol_stack) > 0:
if ch == '(':
symbol_stack.append(ch)
elif ch == ')':
while True:
symbol_pop = symbol_stack.pop()
if symbol_pop == '(':
break
else:
RPN_stack.append(symbol_pop)
else:
comparePriority(ch, RPN_stack, symbol_stack)
else:
symbol_stack.append(ch)
def scanInput(RPN_stack, symbol_stack):
input_string = raw_input()
input_string += '#'
scanEveryone(input_string, RPN_stack, symbol_stack)
def calRPN(RPN_stack):
value_stack = []
RPN_stack.append('#')
for value in RPN_stack:
if value == '#':
return value_stack.pop()
break
if value.isdigit():
value_stack.append(value)
else:
right_value = value_stack.pop()
left_value = value_stack.pop()
cal_string = left_value + value + right_value
value_stack.append(str(eval(cal_string)))
def main():
RPN_stack = []
symbol_stack = []
scanInput(RPN_stack, symbol_stack)
print calRPN(RPN_stack)
if __name__ == '__main__':
main()看完上述内容，你们掌握用Python怎么实现逆波兰表达式的方法了吗？如果还想学到更多技能或想了解更多相关内容，欢迎关注创新互联行业资讯频道，感谢各位的阅读！
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