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你每次取出的是表中的首条记录,当然只能用首条记录登陆了!
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Dim name, password As String
name = TextBox1.Text
Dim com As New OleDb.OleDbCommand("select * from denglu where name='" name "'", conn)
Dim dr As OleDb.OleDbDataReader
conn.Open()
dr = com.ExecuteReader
dr.Read()
password = dr.GetString(1)
If TextBox3.Text = password Then
mesbox("成功!")
Else
msgbox("失败")
End If
dr.Close()
conn.Close()
这种情况下,效率极不好!你能理解什么意思就行了!否则将你的程序改完了!
哈哈简单哪
第一步:登陆网页代码
第二步:登陆以后判断是否登陆成功
有两种方法:1.获取网页代码,判断网页字符有无”登陆成功”字样
源代码:
2.就是判断网页是否跳转到了某一页
源代码:
两种方法结合起来用,可以判断网页是否无法连接
Private Sub BtOk_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Btok.Click
Dim con As OleDbConnection = New OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=Admin.accdb;Persist Security Info=True")
Dim com As OleDbCommand = New OleDbCommand("select * from 用户名", con)
con.Open()
Dim h1 As OleDbDataReader
Dim table As New DataTable
h1 = com.ExecuteReader()
table.Load(h1)
If txtName.Text = "" Then
MsgBox("请输入用户名", MsgBoxStyle.OkCancel + MsgBoxStyle.Exclamation, "错误提示")
ElseIf txtName.Text "" And txtPasswd.Text = "" Then
MsgBox("请输入密码", MsgBoxStyle.OkCancel + MsgBoxStyle.Exclamation, "错误提示")
ElseIf table.Select("用户名='" txtName.Text "'").Length 0 Then
If table.Select("用户名='" txtName.Text "'")(0)("密码").ToString = txtPasswd.Text Then
MsgBox("成功登陆", MsgBoxStyle.OkCancel + MsgBoxStyle.Exclamation, "错误提示") Then
Form1.Show()
Me.Visible = False
Exit Sub
Else
MsgBox("密码错误", MsgBoxStyle.OkCancel + MsgBoxStyle.Exclamation, "错误提示")
End If
Else
MsgBox("用户名不存在", MsgBoxStyle.OkCancel + MsgBoxStyle.Exclamation, "错误提示")
Exit Sub
End If
table.Clear()
h1.Close()
con.Close()
End Sub