快上网专注成都网站设计 成都网站制作 成都网站建设
成都网站建设公司服务热线:028-86922220

网站建设知识

十年网站开发经验 + 多家企业客户 + 靠谱的建站团队

量身定制 + 运营维护+专业推广+无忧售后,网站问题一站解决

迷宫java源代码,JAVA迷宫

求走迷宫问题的算法,要求用Java写的?

public class Maze { private int[][] maze = null;

成都创新互联专注于望城企业网站建设,响应式网站设计,电子商务商城网站建设。望城网站建设公司,为望城等地区提供建站服务。全流程按需求定制网站,专业设计,全程项目跟踪,成都创新互联专业和态度为您提供的服务

private int[] xx = { 1, 0, -1, 0 };

private int[] yy = { 0, 1, 0, -1 };

private Queue queue = null; public Maze(int[][] maze) {

this.maze = maze;

queue = new Queue(maze.length * maze.length);

} public void go() {

Point outPt = new Point(maze.length - 1, maze[0].length - 1);

Point curPt = new Point(0, 0);

Node curNode = new Node(curPt, null);

maze[curPt.x][curPt.y] = 2;

queue.entryQ(curNode); while (!queue.isEmpty()) {

curNode = queue.outQ();

for (int i = 0; i xx.length; ++i) {

Point nextPt = new Point();

nextPt.x = (curNode.point).x + xx[i];

nextPt.y = (curNode.point).y + yy[i];

if (check(nextPt)) {

Node nextNode = new Node(nextPt, curNode);

queue.entryQ(nextNode);

maze[nextPt.x][nextPt.y] = 2;

if (nextPt.equals(outPt)) {

java.util.StackNode stack = new java.util.StackNode();

stack.push(nextNode);

while ((curNode = nextNode.previous) != null) {

nextNode = curNode;

stack.push(curNode);

}

System.out.println("A Path is:");

while (!stack.isEmpty()) {

curNode = stack.pop();

System.out.println(curNode.point);

}

return;

}

}

}

}

System.out.println("Non solution!");

} private boolean check(Point p) {

if (p.x 0 || p.x = maze.length || p.y 0 || p.y = maze[0].length) {

return false;

}

if (maze[p.x][p.y] != 0) {

return false;

}

return true;

} public static void main(String[] args) {

int[][] maze = {

{ 0, 0, 1, 0, 1, 0, 1, 0, 1, 0 },

{ 0, 0, 1, 1, 1, 0, 0, 0, 1, 0 },

{ 0, 1, 0, 0, 1, 0, 0, 0, 0, 1 },

{ 0, 0, 0, 0, 1, 0, 0, 0, 1, 1 },

{ 0, 0, 1, 0, 0, 0, 0, 0, 0, 1 },

{ 1, 0, 1, 0, 1, 0, 0, 1, 0, 0 },

{ 0, 1, 0, 0, 1, 0, 0, 1, 0, 1 },

{ 1, 0, 1, 0, 1, 1, 0, 1, 0, 0 }

};

new Maze(maze).go();

} private class Queue { Node[] array = null;

int size = 0;

int len = 0;

int head = 0;

int tail = 0; public Queue(int n) {

array = new Node[n + 1];

size = n + 1;

} public boolean entryQ(Node node) {

if (isFull()) {

return false;

}

tail = (tail + 1) % size;

array[tail] = node;

len++;

return true;

} public Node outQ() {

if (isEmpty()) {

return null;

}

head = (head + 1) % size;

len--;

return array[head];

} public boolean isEmpty() {

return (len == 0 || head == tail) ? true : false;

} public boolean isFull() {

return ((tail + 1) % size == head) ? true : false;

}

} private class Node { Point point = null;

Node previous = null; public Node() {

this(null,null);

} public Node(Point point, Node node) {

this.point = point;

this.previous = node;

}

} private class Point { int x = 0;

int y = 0; public Point() {

this(0, 0);

} public Point(int x, int y) {

this.x = x;

this.y = y;

} public boolean equals(Point p) {

return (x == p.x) (y == p.y);

} @Override

public String toString() {

return "(" + x + "," + y + ")";

}

}

}

迷宫问题的求解源代码

typedef struct{

int Col,Row;//迷宫的大小

int arr[Rangle][Rangle]; //0表示障碍,1表示是可走的通道,-1表示外界的围墙

}MazeType;

void InitMaze(MazeType

M,int col,int row)

{

//按照用户的输入的行数row和列数col列的二维数组(元素值为1或0)

//设置迷宫的初值,加上边缘的一圈的值

}

void PrintMaze(MazeType M)

{

//根据已经进行二维数组的标记值来输出迷宫(或者其通路)

}

bool Pass(MazeType M,PosType pos)

{//求解迷宫M中,从Start到end的一条路径

//若存在则返回true,否则返回false

Stack S;

InitStack(S);

PosType curpos=start;//设置当前坐标为入口位置;

int curstep=1;

//当前的步数

bool Find=false;

//是否找到出口

ElemType e;

do{

if(Pass(M,curpos))

{

FootPrint(M,curpos);//在当前位置标记为2

e.step=1;

e.seat=curpos;

e.di=1;//初始化为向右边位置移动

Push(S,e);

if(curpos.c==end.ccurpos.r==end.r)//如果找到了出口则终止,并返回true

{

Find=true;

return Find;

}

else{

curpos=NextPos(curpos,1);

curstep++;

}

}

else{//当前位置不能通过

if(!StackEmpty(S)){

Pop(S,e);//将已经走过的最近位置弹出,数据保存在e中

while(e.di==4!(StackEmpty(S))){

MarkPrint(M,e.seat);//留下不能通过的标记

Pop(S,e);

curstep--;

}//while

if(e.di4)//不能通过则改变方向

{

e.di++;//方向顺时针改变一下

Push(S,e);

curpos = NextPos(e.seat,e.di); //求下一个节点

}

}

}

}while(!StackEmpty(S)!Find);

//(!StackEmpty(S)!Find);//当栈不为空且没有找到出口

return

false;//没有找到出口则返回false

请帮忙用数据结构(java版)的知识解决这道迷宫问题的程序代码。

我这是用c写的。你可以看看,希望能帮助到你。

#include"stdlib.h"

#include"stdio.h"

#define N 50

#define M 50

int X;

int maze[N+2][M+2];

struct point{

int row,col,predecessor;

}queue[512];

int head=0,tail=0;

void shoudong_maze(int m,int n){

int i,j;

printf("\n\n");

printf("请按行输入迷宫,0表示通路,1表示障碍:\n\n");

for(i=0;im;i++)

for(j=0;jn;j++)

scanf("%d",maze[i][j]);

}

void zidong_maze(int m,int n){

int i,j;

printf("\n迷宫生成中……\n\n");

system("pause");

for(i=0;im;i++)

for(j=0;jn;j++)

maze[i][j]=rand()%2;

//由于rand()产生的随机数是从0到RAND_MAX

//RAND_MAX是定义在stdlib.h中的,其值至少为32767)

//要产生从X到Y的数,只需要这样写:k=rand()%(Y-X+1)+X;

}

void print_maze(int m,int n){

int i,j;

printf("\n迷宫生成结果如下:\n\n");

printf("迷宫入口\n");

printf("↓");

for(i=0;im;i++)

{printf("\n");

for(j=0;jn;j++)

{if(maze[i][j]==0) printf("□");

if(maze[i][j]==1) printf("■");}

}

printf("→迷宫出口\n");

}

void result_maze(int m,int n)

{ int i,j;

printf("迷宫通路(用☆表示)如下所示:\n\t");

for(i=0;im;i++)

{ printf("\n");

for(j=0;jn;j++)

{if(maze[i][j]==0||maze[i][j]==2) printf("□");

if(maze[i][j]==1) printf("■");

if(maze[i][j]==3) printf("☆");

}

}

}

void enqueue(struct point p)

{ queue[tail]=p;

tail++;

}

struct point dequeue()

{ head++;

return queue[head-1];

}

int is_empty()

{ return head==tail;

}

void visit(int row,int col,int maze[52][52])

{ struct point visit_point={row,col,head-1};

maze[row][col]=2;

enqueue(visit_point);

}

int mgpath(int maze[52][52],int m,int n)

{ X=1;

struct point p={0,0,-1};

if(maze[p.row][p.col]==1)

{ printf("\n===============================================\n");

printf("此迷宫无解\n\n");X=0;return 0;}

maze[p.row][p.col]=2;

enqueue(p);

while(!is_empty())

{p=dequeue();

if((p.row==m-1)(p.col==n-1)) break;

if((p.col+1n)(maze[p.row][p.col+1]==0)) visit(p.row,p.col+1,maze);

if((p.row+1m)(maze[p.row+1][p.col]==0)) visit(p.row+1,p.col,maze);

if((p.col-1=0)(maze[p.row][p.col-1]==0)) visit(p.row,p.col-1,maze);

if((p.row-1=0)(maze[p.row-1][p.col]==0)) visit(p.row-1,p.col,maze);

}

if(p.row==m-1p.col==n-1)

{printf("\n==================================================================\n");

printf("迷宫路径为:\n");

printf("(%d,%d)\n",p.row,p.col);

maze[p.row][p.col]=3;

while(p.predecessor!=-1)

{p=queue[p.predecessor];

printf("(%d,%d)\n",p.row,p.col);

maze[p.row][p.col]=3;

}

}

else {printf("\n=============================================================\n");

printf("此迷宫无解!\n\n");X=0;}

return 0;

}

int main()

{int i,m,n,cycle=0;

while(cycle!=(-1))

{

printf("********************************************************************************\n");

printf(" ☆欢迎进入迷宫求解系统☆\n");

printf(" 设计者:尹旭 林静波(信息2班)\n");

printf("********************************************************************************\n");

printf(" 手动生成迷宫 请按:1\n");

printf(" 自动生成迷宫 请按:2\n");

printf(" 退出 请按:3\n\n");

printf("********************************************************************************\n");

printf("\n");

printf("请选择你的操作:\n");

scanf("%d",i);

switch(i)

{case 1:printf("\n请输入行数:");

scanf("%d",m);

printf("\n");

printf("请输入列数:");

scanf("%d",n);

while((m=0||m50)||(n=0||n50))

{ printf("\n抱歉,你输入的行列数超出预设范围(0-50,0-50),请重新输入:\n\n");

printf("请输入行数:");

scanf("%d",m);

printf("\n");

printf("请输入列数:");

scanf("%d",n);

}

shoudong_maze(m,n);

print_maze(m,n);

mgpath(maze,m,n);

if(X!=0)

result_maze(m,n);

printf("\n\nPress Enter Contiue!\n");

getchar();

while(getchar()!='\n');

break;

case 2:printf("\n请输入行数:");

scanf("%d",m);

printf("\n");

printf("请输入列数:");

scanf("%d",n);

while((m=0||m50)||(n=0||n50))

{printf("\n抱歉,你输入的行列数超出预设范围(0-50,0-50),请重新输入:\n\n");

printf("请输入行数:");

scanf("%d",m);

printf("\n");

printf("请输入列数:");

scanf("%d",n);

}

zidong_maze(m,n);

print_maze(m,n);

mgpath(maze,m,n);

if(X!=0)

result_maze(m,n);

printf("\n\nPress Enter Contiue!\n");getchar();while(getchar()!='\n');break;

case 3:cycle=(-1);

break;

default:printf("\n");

printf("你的输入有误!\n");

printf("\nPress Enter Contiue!\n");

getchar();

while(getchar()!='\n');break;

}

}

}


网站题目:迷宫java源代码,JAVA迷宫
标题来源:http://6mz.cn/article/heiccg.html

其他资讯