java函数的参数传递

The Java programming language always uses call by value. That means that the method gets a copy of all parameter values. In particular, the method cannot modify the contents of any parameter variables that are passed to it.

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For example, consider the following call:

double percent = 10;
harry.raiseSalary(percent);

No matter how the method is implemented, we know that after the method call, the value of percent is still 10.

Let us look a little more closely at this situation. Suppose a method tried to triple the value of a method parameter:

public static void tripleValue(double x) // doesn't work
{
   x = 3 * x;
}

Let's call this method:

double percent = 10;
tripleValue(percent);

However, this does not work. After the method call, the value of percent is still 10. Here is what happens:

There are, however, two kinds of method parameters:

• Primitive types (numbers, Boolean values)

• Object references

You have seen that it is impossible for a method to change a primitive type parameter. The situation is different for object parameters. You can easily implement a method that triples the salary of an employee:

public static void tripleSalary(Employee x) // works
{
   x.raiseSalary(200);
}

When you call

harry = new Employee(. . .);
tripleSalary(harry);

then the following happens:

As you have seen, it is easily possible—and in fact very common—to implement methods that change the state of an object parameter. The reason is simple. The method gets a copy of the object reference, and both the original and the copy refer to the same object.

Many programming languages (in particular, C++ and Pascal) have two methods for parameter passing: call by value and call by reference. Some programmers (and unfortunately even some book authors) claim that the Java programming language uses call by reference for objects. However, that is false. Because this is such a common misunderstanding, it is worth examining a counterexample in detail.

Let's try to write a method that swaps two employee objects:

public static void swap(Employee x, Employee y) // doesn't work
{
   Employee temp = x;
   x = y;
   y = temp;
}

If the Java programming language used call by reference for objects, this method would work:

Employee a = new Employee("Alice", . . .);
Employee b = new Employee("Bob", . . .);
swap(a, b);
// does a now refer to Bob, b to Alice?

However, the method does not actually change the object references that are stored in the variables a and b. The x and y parameters of the swap method are initialized with copies of these references. The method then proceeds to swap these copies.

// x refers to Alice, y to Bob
Employee temp = x;
x = y;
y = temp;
// now x refers to Bob, y to Alice

But ultimately, this is a wasted effort. When the method ends, the parameter variables x and y are abandoned. The original variables a and b still refer to the same objects as they did before the method call (see Figure 4-8).

Figure 4-8. Swapping object parameters has no lasting effect

This discussion demonstrates that the Java programming language does not use call by reference for objects. Instead, object references are passed by value.

Here is a summary of what you can and cannot do with method parameters in the Java programming language:

• A method cannot modify a parameter of primitive type (that is, numbers or Boolean values).

• A method can change the state of an object parameter.

• A method cannot make an object parameter refer to a new object.

标题名称：java函数的参数传递
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