vb.net由点画曲线 vb 曲线

vb如何把已知点绘制成曲线

这是画点的：

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Private Sub Form_Click()

Dim X(7) As Integer, Y(7) As Integer, i%

Form1.Scale (-15, 15)-(15, -15)

Form1.Line (0, 0)-(15, 0)

Form1.Line (0, 15)-(0, 0)

For i = 0 To 12 'Step 1.2 'X轴坐标

Form1.Line (i, 0.1)-(i, 0)

CurrentX = i

CurrentY = -1

Form1.Print i

Next i

For i = 0 To 12 'Step 1.2 'Y轴坐标

Form1.Line (0, i)-(0.3, i)

CurrentX = -0.5

CurrentY = i

Form1.Print i

Next i

X(0) = 0: X(1) = 2: X(2) = 4: X(3) = 6: X(4) = 8: X(5) = 10: X(6) = 12: X(7) = 14

Y(0) = 0: Y(1) = 1: Y(2) = 3: Y(3) = 4: Y(4) = 3: Y(5) = 2: Y(6) = 1: Y(7) = 0

For i = 0 To 7

Form1.PSet (X(i), Y(i)), vbRed

Next i

End Sub

在VB中如何通过已知的几个点绘制样条曲线

Function hypot(ByVal X As Single, ByVal Y As Single)

hypot = Sqr(X ^ 2 + Y ^ 2)

End Function

Sub tspLine(ByVal n As Integer, ByVal ch As Integer, ByVal tx1 As Single, ByVal tx2 As Single, ByVal ty1 As Single, ByVal ty2 As Single)

Dim a(1000) As Single, b(1000) As Single, c(1000) As Single, dX(1000) As Single, dY(1000) As Single

Dim qx(1000) As Single, qy(1000) As Single

Dim tt As Single, bx3 As Single, bx4 As Single, by3 As Single, by4 As Single

Dim cx As Single, cy As Single, t(1000) As Single, px(1000) As Single, py(1000) As Single

Dim u(3000) As Single, v(3000) As Single, i As Integer

num = 0

For i = 1 To n

t(i) = hypot(X(i) - X(i - 1), Y(i) - Y(i - 1))

Next i

Select Case ch

Case 0 '抛物条件

u(0) = (X(1) - X(0)) / t(1): u(1) = (X(2) - X(1)) / t(2)

u(2) = (u(1) - u(0)) / (t(2) + t(1))

tx1 = u(0) - u(2) * t(1)

u(0) = (Y(1) - Y(0)) / t(1): u(1) = (Y(2) - Y(1)) / t(2)

u(2) = (u(1) - u(0)) / (t(2) + t(1))

ty1 = u(0) - u(2) * t(1)

u(0) = (X(n) - X(n - 1)) / t(n): u(1) = (X(n - 1) - X(n - 2)) / t(n - 1)

u(2) = (u(0) - u(1)) / (t(n) + t(n - 1))

tx2 = u(0) + u(2) * t(n)

u(0) = (Y(n) - Y(n - 1)) / t(n): u(1) = (Y(n - 1) - Y(n - 2)) / t(n - 1)

u(2) = (u(0) - u(1)) / (t(n) + t(n - 1))

ty2 = u(0) + u(2) * t(n)

Case 1 '夹持条件

a(0) = 1: c(0) = 0: dX(0) = tx1: dY(0) = ty1

a(n) = 1: b(n) = 0: dX(n) = tx2: dY(n) = ty2

Case 2 '自由条件

a(0) = 2: c(0) = 1

dX(0) = 3 * (X(1) - X(0)) / t(1): dY(0) = 3 * (Y(1) - Y(0)) / t(1)

a(n) = 2: b(n) = 1

dX(n) = 3 * (X(n) - X(n - 1)) / t(n): dY(n) = 3 * (Y(n) - Y(n - 1)) / t(n)

Case 3 '循环条件

a(0) = 2: c(0) = 1

dX(0) = 3 * (X(1) - X(0)) / t(1) - (t(1) * (X(2) - X(1)) / t(2) - X(1) + X(0)) / (t(1) + t(2))

dY(0) = 3 * (Y(1) - Y(0)) / t(1) - (t(1) * (Y(2) - Y(1)) / t(2) - Y(1) + Y(0)) / (t(1) + t(2))

a(n) = 2: b(n) = 1

dX(n) = 3 * (X(n) - X(n - 1)) / t(n)

dX(n) = dX(n) + (X(n) - X(n - 1) - t(n) * (X(n - 1) - X(n - 2)) / t(n - 1)) / (t(n) + t(n - 1))

dY(n) = 3 * (Y(n) - Y(n - 1)) / t(n)

dY(n) = dY(n) + (Y(n) - Y(n - 1) - t(n) * (Y(n - 1) - Y(n - 2)) / t(n - 1)) / (t(n) + t(n - 1))

End Select

'计算方程组系数阵和常数阵

For i = 1 To n - 1

a(i) = 2 * (t(i) + t(i + 1)): b(i) = t(i + 1): c(i) = t(i)

dX(i) = 3 * (t(i) * (X(i + 1) - X(i)) / t(i + 1) + t(i + 1) * (X(i) - X(i - 1)) / t(i))

dY(i) = 3 * (t(i) * (Y(i + 1) - Y(i)) / t(i + 1) + t(i + 1) * (Y(i) - Y(i - 1)) / t(i))

Next i

'采用追赶法解方程组

c(0) = c(0) / a(0)

For i = 1 To n - 1

a(i) = a(i) - b(i) * c(i - 1): c(i) = c(i) / a(i)

Next i

a(n) = a(n) - b(n) * c(i - 1)

qx(0) = dX(0) / a(0): qy(0) = dY(0) / a(0)

For i = 1 To n

qx(i) = (dX(i) - b(i) * qx(i - 1)) / a(i)

qy(i) = (dY(i) - b(i) * qy(i - 1)) / a(i)

Next i

px(n) = qx(n): py(n) = qy(n)

For i = n - 1 To 0 Step -1

px(i) = qx(i) - c(i) * px(i + 1)

py(i) = qy(i) - c(i) * py(i + 1)

Next i

'计算曲线上点的坐标

For i = 0 To n - 1

bx3 = (3 * (X(i + 1) - X(i)) / t(i + 1) - 2 * px(i) - px(i + 1)) / t(i + 1)

bx4 = ((2 * (X(i) - X(i + 1)) / t(i + 1) + px(i) + px(i + 1)) / t(i + 1)) / t(i + 1)

by3 = (3 * (Y(i + 1) - Y(i)) / t(i + 1) - 2 * py(i) - py(i + 1)) / t(i + 1)

by4 = ((2 * (Y(i) - Y(i + 1)) / t(i + 1) + py(i) + py(i + 1)) / t(i + 1)) / t(i + 1)

tt = 0

While (tt = t(i + 1))

cx = X(i) + (px(i) + (bx3 + bx4 * tt) * tt) * tt

cy = Y(i) + (py(i) + (by3 + by4 * tt) * tt) * tt

u1(num) = cx: v1(num) = cy: num = num + 1: tt = tt + 0.5

Wend

u1(num) = X(i + 1): v1(num) = Y(i + 1): num = num + 1

Next i

End Sub

Private Sub Command1_Click()

Dim i As Long

'Picture1.Scale (0, 0)-(640, 550)

DrawWidth = 3

Picture1.Cls

'If Check1.Value Then Command2_Click

'X(0) = 1

'Y(0) = 1

'X(t - 1) = 638

'Y(t - 1) = 548

Picture1.ForeColor = QBColor(10)

For i = 0 To t - 1

Picture1.Line (X(i) - 1, Y(i) - 1)-(X(i) + 1, Y(i) + 1), QBColor(10), B

Picture1.Print i

Next i

Picture1.ForeColor = QBColor(12)

DrawWidth = 1

tspLine t - 1, 2, 0, 0, 0, 0

Picture1.PSet (u1(0), v1(0))

For i = 1 To num - 1

Picture1.Line -(u1(i), v1(i))

'For de = 1 To 12000: Next de 'Sleep 1

Next i

Picture1.ForeColor = QBColor(10)

For i = 0 To t - 1

Picture1.Line (X(i) - 1, Y(i) - 1)-(X(i) + 1, Y(i) + 1), QBColor(10), B

Picture1.Print i

Next i

End Sub

vb.net 绘制实时温度曲线

这个要用GDI+画。要看你.net版本。

以下是VS2005中的一段代码。

Me.PictureBox1.Height = 450

Me.PictureBox1.Width = 880

Dim gr As Graphics '定义画布

Dim bp As New Bitmap(880, 450) '定义位图,并进行赋值

Dim p As New Pen(Color.Black) '定义画笔

p.Width = 2 '宽度2

p.DashStyle = Drawing2D.DashStyle.Solid '样式直线

PictureBox1.Image = bp

gr = Graphics.FromImage(PictureBox1.Image)

gr.FillRectangle(Brushes.White, New Rectangle(0, 0, PictureBox1.Width, PictureBox1.Height))

gr.DrawLine(p, a, b, a, .Height - b) '绘制纵坐标

gr.DrawLine(p, a, .Height - b, .Width - a, .Height - b) '绘制横坐标

vb.net绘制曲线图

。net  其实还是很好绘制图形的

你可以看下 Graphics  类

Dim d As New Bitmap(Me.Width, Me.Height)  ‘一个图片吧

  Dim g As Graphics = Graphics.FromImage(d)’绘制  准备在这个图片是进行

然后  就是你绘制的东西了

线 就是   g.DrawLine()

圆 弧度  就用  g.DrawArc(Pens.Black, New Rectangle(0, 0, 400, 200), 0, 360)

复杂的就是      g.DrawBezier()

等  如果你用的是 VS的  编译  上面都有详细的参数说明

Dim d As New Bitmap(Me.Width, Me.Height)

Dim g As Graphics = Graphics.FromImage(d)

g.DrawArc(Pens.Black, New Rectangle(0, 0, 200, 200), 0, 360)

g.DrawLine(Pens.Red, New Point(0, 0), New Point(200, 200))

g.DrawLines(Pens.Green, New Point() {New Point(0, 0), New Point(50, 40), New Point(50, 80), New Point(90, 70), New Point(100, 400)})

g.DrawBezier(Pens.Yellow, New Point(0, 100), New Point(0, 0), New Point(200, 0）， New Point(200, 200))

g.Dispose()

Me.BackgroundImage = d

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