C#如何实现拼图魔方小游戏-创新互联
小编给大家分享一下C#如何实现拼图魔方小游戏，相信大部分人都还不怎么了解，因此分享这篇文章给大家参考一下，希望大家阅读完这篇文章后大有收获，下面让我们一起去了解一下吧！
先上一张原图
代码也很简单，主要就是通过BitMap分隔现有（后面有时间可以优化下，让玩家自动上传图片，应该会更有意思）图片，然后Random随机打乱分割后图片的顺序，通过点击小方格来完成图片的拼图，为了更方便玩家，每个小方格添加了序号，玩家也可以不参考原图，按照小方格上的序号进行拼图
序号功能实现主要是类MyButton集成父类Button实现：
public class MyButton : Button
{
private int number;
public int Number
{
get
{
return this.number;
}
set
{
this.Text = value.ToString();
this.number = value;
}
}
public MyButton()
{
}
}随机分隔
Random r = new Random();
int[] a = new int[24];
int i = 0;
int b;
bool exist;
while (i != a.Length)
{
exist = false;
b = (r.Next(24) + 1);
for (int j = 0; j < a.Length; j++)
if (a[j] == b) exist = true;
if (!exist) a[i++] = b;
}
for (int j = 0; j < a.Length; j++)
ButtonArray[j].Number = a[j];
// set picture pieces as the background image
int Number;
int Row, Column;
for (int k = 0; k < 5; k++)
{
for (int j = 0; j < 5; j++)
{
if (k == 4)
if (j == 4) break;
Number = ButtonArray[k * 5 + j].Number; //Get The Number Of Button
Row = (Number - 1) / 5;
Column = (Number - 1) - (Row * 5);
ButtonArray[k * 5 + j].Image = CurrentBitmapImage.Clone(new Rectangle(new Point(Column * 75, Row * 75), new Size(75, 75)), System.Drawing.Imaging.PixelFormat.DontCare);
}
}点击小方格，通过改变当前点击的小方格X,Y坐标来更新小方格的位置
private void myButton_LocationChanged(object sender, EventArgs e)
{
MyButton A = sender as MyButton;
YouWin = true;
int ButtonNumber;
this.NumberOfMoves++;
if (ButtonArray == null)
{
this.FrmMain_Load(sender, e);
}
for (int i = 0; i < 5; i++)
{
if (YouWin == false)
break;
else for (int j = 0; j < 5; j++)
{
ButtonNumber = i * 5 + j;
if (i == 4 && j == 4)
break;
else if (GetNumber(ButtonArray[ButtonNumber].Location.X, ButtonArray[ButtonNumber].Location.Y) == ButtonArray[ButtonNumber].Number)
continue;
else
{
YouWin = false;
break;
}
}
}
if (YouWin)
{
if (MessageBox.Show("You Win This Game in " + this.NumberOfMoves.ToString() + " Moves\n\rDo You Want To Play Another Game ?", "Congratulation", MessageBoxButtons.YesNo) == DialogResult.Yes)
this.LoadNewGame();
else
this.Close();
}
}private void myButton_LocationChanged(object sender, EventArgs e)
{
MyButton A = sender as MyButton;
YouWin = true;
int ButtonNumber;
this.NumberOfMoves++;
if (ButtonArray == null)
{
this.FrmMain_Load(sender, e);
}
for (int i = 0; i < 5; i++)
{
if (YouWin == false)
break;
else for (int j = 0; j < 5; j++)
{
ButtonNumber = i * 5 + j;
if (i == 4 && j == 4)
break;
else if (GetNumber(ButtonArray[ButtonNumber].Location.X, ButtonArray[ButtonNumber].Location.Y) == ButtonArray[ButtonNumber].Number)
continue;
else
{
YouWin = false;
break;
}
}
}
if (YouWin)
{
if (MessageBox.Show("You Win This Game in " + this.NumberOfMoves.ToString() + " Moves\n\rDo You Want To Play Another Game ?", "Congratulation", MessageBoxButtons.YesNo) == DialogResult.Yes)
this.LoadNewGame();
else
this.Close();
}
}具体效果如下：
以上是“C#如何实现拼图魔方小游戏”这篇文章的所有内容，感谢各位的阅读！相信大家都有了一定的了解，希望分享的内容对大家有所帮助，如果还想学习更多知识，欢迎关注创新互联成都网站设计公司行业资讯频道！
另外有需要云服务器可以了解下创新互联scvps.cn，海内外云服务器15元起步，三天无理由+7*72小时售后在线，公司持有idc许可证，提供“云服务器、裸金属服务器、高防服务器、香港服务器、美国服务器、虚拟主机、免备案服务器”等云主机租用服务以及企业上云的综合解决方案，具有“安全稳定、简单易用、服务可用性高、性价比高”等特点与优势，专为企业上云打造定制，能够满足用户丰富、多元化的应用场景需求。
文章题目：C#如何实现拼图魔方小游戏-创新互联
转载源于：http://6mz.cn/article/dohdij.html