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class Solution {public String largestMerge(String word1, String word2) {StringBuilder sb = new StringBuilder();
int i = 0, j = 0;
while (i< word1.length() || j< word2.length()) {if (i< word1.length() && word1.substring(i).compareTo(word2.substring(j)) >0) {sb.append(word1.charAt(i));
++i;
} else {sb.append(word2.charAt(j));
++j;
}
}
return sb.toString();
}
}
pythonclass Solution:
def largestMerge(self, word1: str, word2: str) ->str:
# 贪心!
merge = ''
i, j, m, n = 0, 0, len(word1), len(word2)
while i< m or j< n:
# 表明沿着这个方向效益大!
if word1[i:] >word2[j:]:
merge += word1[i]
i += 1
else:
merge += word2[j]
j += 1
return merge
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