Java编程实现五子棋人人对战代码示例-创新互联
利用Java，在控制台操作下，编写的五子棋，作为复习二维数组，面向对象等基础知识。w表示白棋，b表示黑棋
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import java.util.Scanner;
public class MainMethod {
public static char[][] c = new char[10][10];
public static void main(String[] args) {
MainMethod mainMethod = new MainMethod();
mainMethod.init();
int i;
boolean color;
int[] point = new int[2];
Scanner scanner = new Scanner(System.in);
for (i = 1; i < 100; i++) {
mainMethod.draw();// 绘制棋盘
System.out.println("请输入坐标，范围为（0,0）到（9,9）");
int x = scanner.nextInt();
int y = scanner.nextInt();
if (i % 2 == 1)
color = true;
else
color = false;
point[0] = x;
point[1] = y;
if (mainMethod.paint(point, color) == false) {//
System.out.println("下的位置不合理，请重新开始");
break;
}
if (mainMethod.win() == 1) {
mainMethod.draw();
System.out.println("恭喜白棋赢！！");
break;
} else if (mainMethod.win() == -1) {
mainMethod.draw();
System.out.println("恭喜黑棋赢！！");
break;
}
}
if (i == 100)
System.out.println("平局");
}
public char[][] init() {// 初始化棋盘
for (int i = 0; i < c.length; i++) {
for (int j = 0; j < c.length; j++) {
c[i][j] = '+';
}
}
return c;
}
public boolean paint(int[] point, boolean colr) {// 判断下的位置是否正确，若正确改变棋盘
boolean b = true;
int x = point[0];
int y = point[1];
if (inBoard(point) == false || c[x][y] == 'w' || c[x][y] == 'b' || x < 0) {
b = false;
return b;
}
else if (colr == true) {// 白棋下
if (c[x][y] == '+') {
c[x][y] = 'w';
}
}
else if (colr == false) {// 黑棋下
if (c[x][y] == '+') {
c[x][y] = 'b';
}
}
return b;
}
public boolean inBoard(int[] point) {// 判断point是否在棋盘上
int x = point[0];
int y = point[1];
if (x < 0 || y < 0 || x >= c.length || y >= c.length)
return false;
else
return true;
}
public int win() {// 判断输赢，1表示白的赢，-1黑的赢，0暂无输赢
int whoWin = 0;
int[] point = new int[2];
outer: while (true) {
for (int i = 0; i < c.length; i++) {
for (int j = 0; j < c.length; j++) {
if (c[i][j] == 'w') {// 遍历数组，找到的第一个白棋
point[0] = i;
point[1] = j + 4;
if (inBoard(point)) {// 如果存在向右数4个的棋盘
if (c[i][j + 1] == 'w' && c[i][j + 2] == 'w' && c[i][j + 3] == 'w' && c[i][j + 4] == 'w') {
whoWin = 1;
break outer;
}
}
point[0] = i + 4;
point[1] = j + 4;
if (inBoard(point)) {// 如果存在向右,向下数4个的棋盘
if (c[i + 1][j + 1] == 'w' && c[i + 2][j + 2] == 'w' && c[i + 3][j + 3] == 'w'
&& c[i + 4][j + 4] == 'w') {
whoWin = 1;
break outer;
}
}
point[0] = i + 4;
point[1] = j;
if (inBoard(point)) {// 如果存在向下数4个的棋盘
if (c[i + 1][j] == 'w' && c[i + 2][j] == 'w' && c[i + 3][j] == 'w' && c[i + 4][j] == 'w') {
whoWin = 1;
break outer;
}
}
point[0] = i - 4;
point[1] = j + 4;
if (inBoard(point)) {// 如果存在向左,向下数4个的棋盘
if (c[i - 1][j + 1] == 'w' && c[i - 2][j + 2] == 'w' && c[i - 3][j + 3] == 'w'
&& c[i - 4][j + 4] == 'w') {
whoWin = 1;
break outer;
}
}
} else if (c[i][j] == 'b') {
point[0] = i;
point[1] = j + 4;
if (inBoard(point)) {// 如果存在向右数4个的棋盘
if (c[i][j + 1] == 'b' && c[i][j + 2] == 'b' && c[i][j + 3] == 'b' && c[i][j + 4] == 'b') {
whoWin = -1;
break outer;
}
}
point[0] = i + 4;
point[1] = j + 4;
if (inBoard(point)) {// 如果存在向右,向下数4个的棋盘
if (c[i + 1][j + 1] == 'b' && c[i + 2][j + 2] == 'b' && c[i + 3][j + 3] == 'b'
&& c[i + 4][j + 4] == 'b') {
whoWin = -1;
break outer;
}
}
point[0] = i + 4;
point[1] = j;
if (inBoard(point)) {// 如果存在向下数4个的棋盘
if (c[i + 1][j] == 'b' && c[i + 2][j] == 'b' && c[i + 3][j] == 'b' && c[i + 4][j] == 'b') {
whoWin = -1;
break outer;
}
}
point[0] = i - 4;
point[1] = j + 4;
if (inBoard(point)) {// 如果存在向左,向下数4个的棋盘
if (c[i - 1][j + 1] == 'b' && c[i - 2][j + 2] == 'b' && c[i - 3][j + 3] == 'b'
&& c[i - 4][j + 4] == 'b') {
whoWin = -1;
break outer;
}
}
}
}
}
whoWin = 0;
break outer;
}
return whoWin;
}
public void draw() {// 绘制棋盘
for (int i = 0; i < c.length; i++) {
for (int j = 0; j < c.length; j++) {
System.out.print(c[i][j] + " ");
}
System.out.println();
}
}
} 标题名称：Java编程实现五子棋人人对战代码示例-创新互联
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